2 kumpulan materi soal dan jawaban lengkap: Teori Bilangan

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Jumat, 01 Juni 2018

Olimpiade Teori Bilangan

Belajar Modulo Dengan Cara Sederhana

Juni 01, 2018 Comment

$2 \mid 4$ sebab untuk $k=7$ sehingga $2k=14$

$5 \mid 30$ sebab untuk $k=6$ sehingga $5k=30$

$3 \nmid 10$ sebab tidak ada nilai $k$ sehingga $3k=10$

$27\equiv 2\ mod\ \left ( 5 \right )$ artinya $27$ dibagi $5$ sisa $2$

$48\equiv 6\ mod\ \left ( 7 \right )$ artinya $48$ dibagi $7$ sisa $6$

$a\equiv b\ mod\ \left ( n \right )$ artinya $a$ dibagi $n$ sisa $b$

$27\equiv 2\ mod\ \left ( 5 \right )$ $\Rightarrow$ $5 \mid (27-2)$ atau $5$ faktor dari $(27-2)$

$48\equiv 6\ mod\ \left ( 7 \right )$ $\Rightarrow$ $7 \mid (48-6)$ atau $7$ faktor dari $(48-6)$

$13\equiv 1\ mod\ \left ( 4 \right )$ $\Rightarrow$ $4 \mid (13-1)$ atau $4$ faktor dari $(13-1)$

(1) Sisa $16^{2}$ dibagi $3$ adalah...(2) Sisa $17^{20}$ dibagi $5$ adalah...Panduan Pemula Belajar Aritmetika ModularCMIIWJADIKAN HARI INI LUAR BIASA! - WITH GOD ALL THINGS ARE POSSIBLE

endengar kata modulo pertama kali seakan Belajar Modulo Dengan Cara Sederhana

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